Sherlock and Squares

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/*
 Formula to find number of perfect square between two numbers:
 [ floor(sqrt(b)) - ceil(sqrt(a)) + 1;  ]

 why floor b ?
 ----- Because we have to take before b, i mean <=b.
 why ceil a ?
 ----- Because we have to take after a, i mean >=a.
 [ for(i=a; i<=b;i++)  ]

 Therefore, the result will be [ floor and ceil square root difference between two numbers plus 1]

*/

#include<bits/stdc++.h>
using namespace std;

typedef long long LL;

int main()
{
    int t;
    cin >> t;
    while(t--)
    {
        LL a,b,i,cnt=0;
        cin >> a >> b;

        LL res = floor(sqrt(b)) - ceil(sqrt(a)) + 1;
        cout << res << "\n";
    }

    return 0;
}

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