P_Sarker Coding House

// Accepted Code Link: B. Interesting drink // Mnaual //#include<stdio.h> //#include<iostream> //#include<algorithm> //#include<vector> //#include<cstring> //#include<cmath> //#include<map> #include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) #define outs(x) cout << x << " " #define outn(x) cout << x << "\n" #define sf scanf #define pf printf #define high 1000010 typedef long long LL; typedef vector<LL>vll; vll ar; //upper bound LL khoj(LL lo, LL hi, LL itm) {     LL mid;     while(lo <= hi)     {         mid = (lo + hi) / 2;         if(ar[mid] == itm) lo = mid+1;         else if(ar[mid] > itm) hi = mid - 1;         else if(ar[mid] < itm) lo=mid+1;     }  ...

// This is all about 311 lines code // I am request you to please see other code if you are incapable to solve it Accepted Code Link: B. Chris and Magic Square //#include<stdio.h> //#include<iostream> //#include<algorithm> //#include<vector> //#include<cstring> //#include<cmath> //#include<map> #include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) #define outs(x) cout << x << " " #define outn(x) cout << x << "\n" #define sf scanf #define pf printf #define high 505 typedef long long LL; LL ar[high][high]; LL d=0 , diagsum1=0, diagsum2=0; bool gotnm=false; int n , row=0, col=0; void checkWhole() {     LL rowsum=0, colsum=0, tmprow=0, tmpcol=0 , d1=0, d2=0 , ans1=0, ans2=0;     int i,j;     bool decision=false;     for(i=0; i<n; i++)     {         rowsum=0;  ...

//#include<stdio.h> //#include<iostream> //#include<algorithm> //#include<vector> //#include<cstring> //#include<cmath> //#include<map> #include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) #define outs(x) cout << x << " " #define outn(x) cout << x << "\n" #define sf scanf #define pf printf typedef long long LL; int main() {     //fast;     LL n, k;     while(~sf("%I64d %I64d", &n , &k))     {         LL lim = 0;         lim = n % 2 == 0 ? n / 2 : (n / 2) + 1;         if(k > lim)         {             // even             pf("%I64d\n", 2 * (k - lim)) ;   ...

#include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) #define outs(x) cout << x << " " #define outn(x) cout << x << "\n" #define sf scanf #define pf printf int main() {     fast;     int n, h;     while(cin >> n >> h)     {         int sum=0;         int x;         while(n--)         {             cin >> x;             if(x > h) sum+=2;             else sum++;         }         outn(sum);     }     return 0; }

/* You can just change i mean convert each character to it's previous character until you have not found 'a' to find lexicographically minimum.If you get 'a' that means it is already lexicographically minimum, then change any a character to its previous as one time. */ //#include<stdio.h> //#include<iostream> //#include<algorithm> //#include<vector> //#include<cstring> //#include<cmath> //#include<map> #include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) #define outs(x) cout << x << " " #define outn(x) cout << x << "\n" //int ar[28]; typedef long long LL; //void ascii() //{ //    for(int i=97; i<=122; i++) //    { //        ar[i] = i; //    } //} int main() {     fast;     //ascii();     string s;     wh...

#include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) typedef long long LL; int main() {     fast;     LL n, b, d;     while(cin >> n >> b >> d)     {         LL cnt=0 , x , sum=0 ;         while(n--)         {             cin >> x;             if(x <= b) sum+=x;             if(sum > d) cnt++, sum=0;         }         cout << cnt << "\n";     }     return 0; }

// Accepted. // Link:  Codeforces AC link of problem Link/Cut Tree #include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) #define high 300010 typedef unsigned long long LL; //LL power(LL x, int y) //{ //    if(y == 0) return 1; // //    LL tmp = power(x, y/2); // //    if(y % 2 == 0) //    { //        return tmp * tmp; //    } // //    else //    { //        return x * tmp * tmp; //    } //} int main() {     fast; //    LL x = 923523399718980912, y = 18686596544687500000; //    string s = x > y ? "x boro" : "y boro"; //    cout << s;     LL l, r, k;     while(cin >> l >> r >> k)     ...

#include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) #define high 300010 typedef long long LL; int main() {     fast;     LL n;     while(cin >> n)     {         LL ans = (n%5) ? (n/5) + 1 : n/5;         cout << ans << "\n";     }     return 0; }

#include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) #define high 300010 typedef long long LL; LL ar[high]; int main() {     fast;     LL n;     while(cin >> n)     {         LL i;         for(i=0; i<n; i++)         {             cin >> ar[i];         }         sort(ar, ar+n);         LL ans = (n&1) ? ar[n/2] : ar[n/2 - 1];         cout << ans << "\n";     }     return 0; }

#include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) int ret(char ch) {     if(ch == 'a') return 1;     else if(ch == 'b') return 2;     else if(ch == 'c') return 3;     else if(ch == 'd') return 4;     else if(ch == 'e') return 5;     else if(ch == 'f') return 6;     else if(ch == 'g') return 7;     else if(ch == 'h') return 8; } int ar[9][9]; void init() {     int i,j;     for(i=1; i<=8; i++)     {         for(j=1; j<=8; j++)         {             ar[i][j] = 1;         }     } } int main() {     fast;     int n;     char c;     init();  ...

#include<bits/stdc++.h> using namespace std; typedef map<int, bool>mpbi; struct my {     int in, v; }; bool cmp(my  a, my b) {     return a.v < b.v; } my ar[5010]; //int ar[100]; int main() {     ios_base::sync_with_stdio(false);     int n;     mpbi mp;     while(cin >> n)     {         mp.clear();         int i=0 , x, quotient=0 , one=0, two=0, three=0, mini=100000 ;         for(i=0; i<n; i++)         {             cin >> x;             ar[i].in = i;             ar[i].v = x;             //ar[i]...

The Accepted Code is on github Solution Link: Solution Link of UVa 11614 Etruscan Warriors Never Play Chess

// Accepted #include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(false) #define out(x) cout << x << "\n" typedef unsigned long long ull; string ans=""; void fun_ek(int n) {     while(n--)     {         ans+="0";     } } int main() {     fast;     string s;     while(cin >> s)     {         ans="";         if(s[0] != '0') ans+=s[0];         int b=0 , k=1;         string tmp="";         while(s[s.length()-k] != 'e')         {             tmp+=s[s.length()-k];             k++;  ...

#include<bits/stdc++.h> using namespace std; typedef long long LL; typedef vector<LL>vll; typedef map<LL, bool>mpbl; #define high 1000000000 #define fast ios_base::sync_with_stdio(false) int len=0; vll v; mpbl mp; void funkey() {     LL i;     for(i=1; ; i++)     {         if(((i * (i+1)) / 2 ) > high)         {             //cout << i << " " << i+1;             break;         }         v.push_back(((i * (i+1)) / 2));         mp[((i * (i+1)) / 2)] = true;     }     //for(i=0; i<50; i++) cout << v[i] << " ";     len = v.size(); } int khoj(int lo, int hi, LL itm) { ...

#include<bits/stdc++.h> using namespace std; typedef long long LL; int main() {     ios_base::sync_with_stdio(false);     int n , t;     while(cin >> n >> t)     {         if(t==10)         {             if(n==1)             {                 cout << "-1\n";                 continue;             }             cout << "1";             for(int i=2; i<=n; i++) cout << "0";      ...

#include<bits/stdc++.h> using namespace std; typedef long long LL; bool isLeap(LL n) {     return (n % 400==0 or (n%4==0 and n%100!=0)); } int main() {     ios_base::sync_with_stdio(false);     LL n;     while(cin >> n)     {         LL day=0;         for(LL i=n; ; i++)         {             if(isLeap(i)) day+=366;             else day+=365;             if(day%7==0 and isLeap(n) == isLeap(i+1) and n!=i+1)             {                 cout << i+1 << "\n";       ...

// Accepted // Formula: ( (A^n) - 1 / A - 1) * B + ( (A ^ n) * x) // You have to do Modular Multiplicative Inverse due to (A - 1) ^ -1 #include<bits/stdc++.h> using namespace std; typedef long long LL; #define mod 1000000007 LL bigmod(LL a , LL b, LL c) {     if(b==0) return 1;     if(b % 2 == 0)     {         LL r = bigmod(a, b/2 , c);         return ((r%c) * (r%c)) % c;     }     else     {         return (((a%c) * bigmod(a, b-1 , c) % c)) % c;     } } int main() {     ios_base::sync_with_stdio(false);     LL a , b , n , x;     while(cin >> a >> b >> n >> x)     {         LL tmp, t1, t2, ans;         if(a == 1)  ...

**********************************  Solution 1 ***************************** #include<bits/stdc++.h> using namespace std; #define tofast ios_base::sync_with_stdio(false) int main() {     tofast;     int n, a , b;     while(cin >> n >> a >> b)     {         int ans=0;         for(int i=a+1; i<=n ; i++)         {             if(n - i <= b) ans++;         }         cout << ans << "\n";     }     return 0; } ******************************Solution 2******************************************* #include<bits/stdc++.h> using namespace std; #define tofast ios_base::sync_with_stdio(false) int main() {     tofast...

#include<bits/stdc++.h> using namespace std; int main() {     int n;     while(cin >> n)     {         int x , tmp=15, ans=0;         bool bore=false;         for(int i=0; i<n; i++)         {             cin >> x;             if(!bore)             {                 if(x > tmp)                 {                     bore = true;         ...